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clanker: veet-hard-problems (run)
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problems/hard/task-scheduler/solution.py
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problems/hard/task-scheduler/solution.py
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"""
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Task Scheduler
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You're building a CI/CD pipeline orchestrator. Given a set of build tasks
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with durations and dependency requirements, determine the minimum total
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time to complete all tasks when independent tasks can run in parallel.
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Also detect if the dependency graph contains a cycle (making the build
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impossible).
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Each task is represented as (name, duration, dependencies) where
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dependencies is a list of task names that must complete before this
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task can start.
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Example 1:
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Input: tasks = [("compile", 3, []), ("test", 5, ["compile"]), ("lint", 2, []), ("deploy", 1, ["test", "lint"])]
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Output: (9, ["compile", "test", "deploy"])
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Explanation: compile(3) -> test(5) -> deploy(1) = 9. lint(2) runs in parallel and finishes before deploy starts. The critical path is compile -> test -> deploy.
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Example 2:
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Input: tasks = [("A", 2, ["B"]), ("B", 3, ["A"])]
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Output: (-1, [])
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Explanation: Circular dependency between A and B makes execution impossible.
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Example 3:
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Input: tasks = [("X", 4, []), ("Y", 4, []), ("Z", 1, ["X", "Y"])]
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Output: (5, ["X", "Z"])
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Explanation: X and Y run in parallel (both take 4). Z waits for both, then takes 1. Critical path is X(4) -> Z(1) = 5 (or equivalently Y -> Z). Return either.
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Constraints:
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- Task names are unique non-empty strings
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- Durations are positive integers (>= 1)
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- Dependencies reference other task names in the list
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- Return (-1, []) if a cycle exists
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- The critical path is the longest path through the dependency graph
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- If multiple critical paths have the same length, return any one
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- The critical path list is ordered from first task to last
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- All tasks must be completed; the answer is the makespan
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"""
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def schedule_tasks(
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tasks: list[tuple[str, int, list[str]]],
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) -> tuple[int, list[str]]:
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"""Return (min_total_time, critical_path) or (-1, []) if cycle exists."""
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pass # Your implementation here
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